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We have `y=f(x) =y cos^(-1)(2^(x))` <br> Now for `x in R, 2^(x) in (0,oo)` <br> But f(x) is defined if `2^(x) in (0, 1]`, <br> So `x in (-oo, 0]," which is the domain of y=f(x)` <br> Now for `0lt2^(x)le1` <br> `cos^(-1)1lecos^(-1)(2^(x))ltcos^(-1)0` <br> `:." "0lecos^(-1)(2^(x))ltpi//2` <br> Thus, when `xto-oo,cos^(-1)(2^(x))to(pi)//2"and "f(0)=0` <br> Also `f'(x)=(-2^(x)log_(e)2)/(sqrt(1-4^(x)))lt0,` hence f(x) is a decreasing function. <br> From the above discussion, the graph of the function is as shown in the following figure. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_GRA_C04_E01_011_S01.png" width="80%">Transcript

Time | Transcript |
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00:00 - 00:59 | hello friends to as you can see in this question it is given that draw the graph of y equals to Cos inverse 2 to the power we have to draw this did what is given to us so it is given to me that Y = Cos inverse 2 to the power x now it's belongs to the 2 to the power x belongs 202 infinity is defined between this with the dormant 26 belongs to from this we can see that explains 2 minus infinity 20 what is its which is the which is the domain this is the domain y = 2 X |

01:00 - 01:59 | is between 0 to 100 this part prequel 20 ke this part is like to the power x and this part will be fibre to so when your stands to minus infinity then the Cos inverse 2 to the power x is 5 by 2 in at = 200 so when you then differentiated by differentiating you will get to the power x |

02:00 - 02:59 | log 3 log base 2 and root 1 minus 4 to the power x which is less than zero so this part will be less than zero by this is a decreasing function if x is decreasing function so from this now we can draw the graph of this function on drawing the graph of this this is my wife's is ok this is my xxxx2 -1 -2 -3 and -4 |

03:00 - 03:59 | 9 because it is from that that means it is between these values and its inverse its graph will be like this this is my final graph for this function |

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